Question

Hydrochloric acid (HCI) reacts with sodium hydroxide (NaOH) to form sodium chloride (NaCI) and water. If DH--56.13 kJ/mol and DS-79.11 J/mol x K, what is the temperature of the reaction if DG--80.89 kJ/mol? 40.0°C 75°C 0.313°C 154°C 313 C

Answer 1

- NaCl +H₂O HCl + NaOH Ди” Ди Dso is osº DG is AG D and a both signs have some meaning. AG - DMO - TAS° of DG` = Diº – T DS° DH° = -56-13kJ/mol = -56-13X103 J/mol DS° = 79.11 J/mol XK DG = -80.89 kJ/mol = -80.89 X 103 J/mol Tis temperature DGY = DM° – TDS° 56 kJ -80.8 mol mol XK mol -80-89 to - 56-13 kati ya - T (79.1. 2018K) -80.89 km + 56-13 key = - T (19-1 FIXK)

-24.76 km y = -7 (791. Hd xx) _24.76X100 pm on I - 79.11 J molxK 312.98 K = T 313k = I Temperature , T =313K T = (313 – 273) °C T = 40.0°C