Question

A horizontal wire is hung frem the celing of a room by two massless strings. The wire has a length of 0.11 m and a mass of 0.009 kp. A unifom magnetic field of magnitude 0.065 T is directed from the ceiling to the floor. When a current of - 23 A exists in the wire, the wire swings upward and, at equi ibrium, makes an angle with respest to the vertical, as the drawing shows. Find (a) the angle and (b) the tension in each of the two strirngs. maespect lo an anole tu) a. (b) T-

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Answer #1

Given is:-

Length of the wire L = 0.11m

Mass of the wire  m 0.009kg

Magnetic field  В 0.0657.

Current  I=23A

Now,

part-a

According to Newton’s second law, the weight of the wire is balanced by the vertical component of the tension force, therefore

2T cos phi = mg eq-1

and the magnetic force is balanced by the horizontal component of the tension force

1 LB = 21, sino eq-2

we know that  tano - sino CoS

Hence dividing eq-2 by eq-1 we get

ILB tano =- mg

or

>- tan mg

by plugging all the values we get

o tan-123) 0.11) (0.065 (0.009) (9.8)

ψ-tan-1 (1.86451)

which gives us

61.8

Part-b

From eq-1 we get

2T cos phi = mg

by plugging all the values we get

2Tcos(61.8) = (0.009) (9.8)

which gives us

T-0.086N

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