On aircraft carriers, catapults are used to accelerate jet aircraft to flight speeds in a short...
On aircraft carriers, catapults are used to accelerate jet aircraft to flight speeds in a short distance. One such catapult takes a 18,200-kg jet from 0 to 65 m/s in 2.9 s. (Assume the catapult acts in the positive horizontal direction. Indicate the direction with the sign of your answer where appropriate.)
(a) What is the acceleration of the jet in m/s2?
(b) What is the acceleration of the jet in g's?
(c) How far does the jet travel while it is accelerating?
(d) How large is the force that the catapult must exert on the jet?
Homework Answers
a) 65/2.9 = 22.41 m/s^2
b) a (in g’s) = 22.41/9.8 = 2.29 g’s
b)d = 1/2 a t^2 = 0.5 x 22.41 x 2.9^2 = 94.25 m
c)F = ma = 18,200 x 22.41 = 407,862 N.
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On aircraft carriers, catapults are used to accelerate jet
aircraft to flight speeds in a short...
On aircraft carriers, catapults are used to accelerate jet aircraft to flight speeds in a short...
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I dont understand how we get the position and velocity vector for b. Also, I think we need the initial velocity to solve...
I dont understand how we get
the position and velocity vector for b. Also, I think we need the
initial velocity to solve for part a but it is not given and it
cannot be zero since the jet is being catapulted.
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Use Matlab... Use given variables... %Set values of parameters H0 = 4000 ; v0 = 0; vplane = 38.9...
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H0 = 4000 ;
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vwind = 7.0;
g = -9.81;
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dt = 0.1;
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%To minimize edits, let v = vertical velocity, and vx = horizontal
velocity
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v(1) = v0;
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I dont understand how we get
the position and velocity vector for b. Also, I think we need the
initial velocity to solve for part a but it is not given and it
cannot be zero since the jet is being catapulted.
32. A Lockheed Martin F-35 II Lighting jet takes off from an aircraft carrier with a runway length of 90 m and a takeoff speed 70 m/s at the end of the runway. Jets are catapulted into airspace...
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Use Matlab... Use given variables...
%Set values of parameters
H0 = 4000 ;
v0 = 0;
vplane = 38.9;
vwind = 7.0;
g = -9.81;
td = 45;
dt = 0.1;
%initial conditions
%To minimize edits, let v = vertical velocity, and vx = horizontal
velocity
y(1) = H0;
v(1) = v0;
t(1) = 0;
x(1) = 0;
vx(1) = vplane;
%loop until parachutist reaches the ground
%Calculate te horizontal distance traveled before and after the
parachute opens
d_free =...
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