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1.00 mºto V - 3.00 m along the path shown in the figure below. The initial pressure is PA-2.00 x 10 Pa and there are 92.2 mol
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Answer #1

work done w=fAV : E-RE Vig-VA] = -2x105 {3-13 Tw = -4X1055 : using ideal gas equation . PUEnRT PVA ARTA PV = nRTB - P(UB-YA)

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