Question

2) Two charges, one with magnitude +4.85 x 10-6 C and the other with magnitude -3.93 x 10-6 C, are separated by a distance of 0.485 cm. a. What is the magnitude of the electrostatic force on the charge? b. What is the direction of the electrostatic force?

Answer 1

here,

q1= 4.95 * 10^-6 C

q2 = - 3.93 * 10^-6 C

r = 0.485 cm = 4.85 * 10^-3 m

a)

the magnitude of the electrostatic force , F = K * q1 * q2 /r^2

F = 9 * 10^9 * 4.95 * 10^-6 * 3.93 * 10^-6 /(4.85 * 10^-3)^2 N

F = 7.44 * 10^3 N

b)

this force is attrative in nature

3)

q1 = 3.55 uC = 3.55 * 10^-6 C

q2 = - 8.35 uC = - 8.35 * 10^-6 C

the magnitude of the electrostatic force , F = K * q1 * q2 /r^2

355 = 9 * 10^9 * 3.55 * 10^-6 * 8.35 * 10^-6 /(r)^2

solving for r

r = 2.74 * 10^-2 m

r = 2.74 cm

the distance between the charges is 2.74 cm