Components of 4kN force
Horizontal component = 4 x Cos (30) = 3.46 kN
Vertical component = 4 x Sin(30) = 2 kN
Moment of a force about a point = Force x Perpendicular distance from line of force to that point
Hence , Moment about O = 3 x 0 + 5 x 0 + 2 x 300 + 3.46 x 300 - 2 x 700 [ 3kN & 5kN force passes through O , -ve sign for counterclockwise direction]
= +238 kN.mm
= 238 Nm (Clockwise)
Determine the resulting moment with respect to point O. use the scalar formula for the calculation...
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