Question

-311 R24 40 lb 1 1 sin 45 60 lb 2 cos 30 (c) 2 m -7 kN m O (c)

For each following cases determine the moment of the force about point O.

Answer 1

© 2 Ft tolb 1300 * 4 ft 2 lossoft moment of the force about point o due to to lb for {M. = Fx8, Perpendicular distance = 40 lb x (4 + 2 los 30 Cosso')] ft = 229.28 lb ft (elockwise) av 3ft th Zisiner Isin45o fr Moment about beint o - 2m {mo = for 60 lbs x C I Sin 45°) 44 42.43 lb-ft u ant block urse) Il Im Emo = for TKN 7XNX(4-1) perpendicular distana = 7X10²NX 3m 21x103 Mo=21 KN-m 3m N-m anticay surse