`Hey,
Note: Brother in case of any queries, just comment in box I would be very happy to assist all your queries
clc
clear all
s=[140,220,310,410]';
t=[9:12]';
disp('Average speed is');
Vav=t\s
Kindly revert for any queries
Thanks.
FITTING A STRAIGHT LINE 1-6 Fit a straight line to the given points (x, y) by...
QUESTION6 Traveling with an initial speed of vo 53 km/h, a car accelerates at 3,259 km/h2 along a straight road. What would be the distance traveled (in meters) to reach a final speed for the car to reach a final speed v 106 km hr? QUESTION7 The velocity of a particle is v = 2.1/ + (3-20 j mis, where t is in seconds. Ifrs 0 when t = o, determine the displacement of the particle in the x direction...
FITTING A QUADRATIC PARABOLA 8-11 Fit a parabola (7) to the points (x, y). Using MATLAB 10. hr] Worker's time on duty, y [sec] = His/her reaction time, (t, y) (1, 2.0), (2, 1.78), (3,1.90), (4, 2.35), (5, 2.70) FITTING A QUADRATIC PARABOLA 8-11 Fit a parabola (7) to the points (x, y). Using MATLAB 10. hr] Worker's time on duty, y [sec] = His/her reaction time, (t, y) (1, 2.0), (2, 1.78), (3,1.90), (4, 2.35), (5, 2.70)
The graph above shows the speed of a car traveling in a straight line as a function of time. At t=0 s the speed of the car is 2.00 m/s. it accelerates uniformly and reaches a speed of 6.20 m/s in 8.00 s. Calculate the distance traveled by the car from a time of 2.40 to 7.20 s.
A car travels in a straight line a distance of 8.4 km at an average speed of 70 km / h before stopping due to lack of fuel. Following this stop, the driver of this car walks for 30 minutes over a distance of 2.0 km to get to the nearest gas station. at. What is the total distance the driver has traveled between the beginning of the journey of her car and until he arrives at the gas station?...
Increasing Velocity V, 0 1 2 3 4 5 6 7 8 The graph a distance traveled by the car from a time of 1.60 to 3.30 s the speed of a car traveling in a straight line as a function of time. At t 0 s the speed of the car is 2.30 m/s. It accelerates uniformly and reaches a speed of 9.70 m/s in 8.00 s. Calculate Tries 4/6 Previous Tries
The graph shows the speed of a car traveling in a straight line as a function of time. The value of vc is 4.10 m/s and the value of vd is 7.40 m/s. Calculate the distance traveled by the car from a time of 2.30 to 6.30 seconds. Vd Tl 0 2 3 4 5 6 8 1 7 TIme, s
The velocity of a particle traveling in a straight line is given by v (6t-3t2) m/s, where t is in seconds. Suppose that s 0 when t0. a. Determine the particle's deceleration when t3.6s b. Determine the particle's position when t 3.6 s C. How far has the particle traveled during the 3.6-s time interval? d. What is the average speed of the particle for the time period given in previous part?
the velocity of a particle traveling in a straight line is given by v=(6t-3t^2)m/s, where t is in seconds, if s=0 when t= 0. determine the particles deceleration and position when t=3s. how far has the particle traveled during the 3s time interval and what is its average speed?
The graph shows the speed of a car traveling in a straight line as a function of time. 仂 0 01 2 3 45 6 78 Time, s The value of vc is 4.00 m/s and the value of Vd is 7.10 m/s. Calculate the distance traveled by the car from a time of 2.10 to 7.60 seconds 1705 m Note that the change in the acceleration of the car occurs at 1.00s, 3.00s and 5.00s Submit Answer Incorrect. Tries...
please solve it with codes in Matlab 3) 6 11 12 15 17 19 TO 7 12 :12 Use least-squares regression to fit a straight line to the list of data in the accompanying table. Give the slope and the intercept Compute the correlation coefficient Give an estimation of y for r 10 Slope: Intercept: Your answer: Your Answer Page 1 of 1 3) 6 11 12 15 17 19 TO 7 12 :12 Use least-squares regression to fit a...