This is a Mastering Physics Question Each plate of a parallel-plate capacator is a square with...
Each plate of a parallel-plate capacator is a square with sidelength ,and the plates are separated by a distance . Thecapacitor is connected to a source of voltage.A plastic slab ofthickness and dielectric constant is inserted slowly between the plates over the time period until the slab is squarely between the plates. While theslab is being inserted, a currentruns through thebattery/capacitor circuit.Assuming that the dielectric is inserted at aconstant rate, find the current as the slab is inserted.Express answer in...
Changing Capacitance Yields a Current Each plate of a parallel-plate capacator is a square with side length r, and the plates are separated by a distance d. The capacitor is connected to a source of voltage V. A plastic slab of thickness d and dielectric constant K is inserted slowly between the plates over the time period At until the slab is squarely between the plates. While the slab is being inserted, a current runs through the battery/capacitor circuit. (Figure...
Mastering Physics: Homework 3 session.masteringphysics.com <Homework 3 Item 1 A parallel plate capacitor has square plates that are 600 cm on each side and 4.10 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 6.00 cm on a side and 205 mm thick. One slab is pyrex glass and the other is polystyrene Part A If the potential difference between the plates is 730 V, how much electrical energy is stored in...
Problem 5 (16 +8 Points) A parallel plate capacitor biased under a constant voltage Vo is shown in the figure below. Two parallel plates are separated by a distance of d and filled with a medium whose permittivity is ε,-ε-The parallel plates have a height of h and a width of t not shown in the figure). A dielectric slab with a thickness of d/3 is inserted in between the two parallel plates. The dielectric slab has a permittivity of...
A parallel plate square capacitor with sides 10 cm in length are separated by a 3.0 cm gap. The capacitor is connected to a 9.0 V power supply. A dielectric, with dielectric constant κ = 3.0 is inserted between the plates while the capacitor remains connected to the power supply. What is the magnitude of electric field between the plates due solely to the polarization of the dielectric? answer: 2Q/ E0A
A 2.0 μF parallel-plate air-filled capacitor is connected across a 10 V battery. (a) Determine the charge on the capacitor and the energy stored in the capacitor. (b) An identical 2.0 μF parallel-plate air-filled capacitor is connected across a 5 V battery, and a dielectric slab with dielectric constant κ is inserted between the plates of the capacitor, completely filling the region between the plates, while the battery remains connected. The energy stored in this capacitor is four times that...
The figure shows a parallel-plate capacitor of plate area A and plate separation d. A potential differenceV0 is applied between the plates. While the battery remains connected, a dielectric slab of thickness b and dielectric constant κ is placed between the plates as shown. Assume A = 130 cm2, d = 1.94 cm, V0 = 72.6 V, b = 0.735 cm, and κ = 3.15. Calculate (a) the capacitance,(b) the charge on the capacitor plates,(c) the electric field in the gap, and(d)...
Question 4 1 pts A parallel-plate capacitor of capacitance C has the area of plates A and distance between plates d. Capacitor is connected to the battery of voltage V, fully charged and stays connected. A slab of dielectric material with dielectric constant 4 is then inserted into capacitor, completely filling region between plates. Electric field between plates of capacitor: O stays the same O increases twice O decreases twice O decreases 4 times O increases 4 times
A parallel-plate capacitor of capacitance Co, plate area A, spacing d is charged to voltage V. and then disconnected from the charging battery. A slab with dielectric constant K and thickness d/2 is thrust into the capacitor, as shown in the figure below; the slab is exactly halfway between the plates. к (a) What is the new capacitance in terms of Co? (b) What is the ratio of the stored energy before to that after the slab is inserted (U/0.)?...
Question 4 1 pts A parallel-plate capacitor of capacitance C has the area of plates A and distance between plates d. Capacitor is connected to the battery of voltage V, fully charged and then disconnected. A slab of dielectric material with dielectric constant 4 is then inserted into capacitor, completely filling region between plates. Electric field between plates of capacitor: decreases twice stays the same increases twice decreases 4 times increases 4 times