A ball is dropped onto a smooth floor. It deforms elastically, and then returns to its original shape as it rebounds to its original height. Air friction is negligible. Which of the following statements best describes the thermodynamic change in the ball?
a. The entropy of the ball increases b. The entropy of the ball is unchanged c. The temperature of the ball decreases d. The enthalpy of the ball decreases
The answer is entropy of the ball is unchanged.
Since it is elastic deformation so the energy gained due to compression while hitting the ground is equal to the energy released when the ball restore its original shape. Overall, we can see that energy released = energy gained so there is no release or absorption of energy per unit time during the whole process. Hence, Entropy of the ball does not change.
While we know that during a process work done is practically zero moreover air friction almost nil. So, there is no change in temperature. and for this reason the entropy also doesnot change.
If any doubt feel free to comment.
A ball is dropped onto a smooth floor. It deforms elastically, and then returns to its...
A soft tennis ball is dropped onto a hard floor from a height of 1.55 m and rebounds to a height of 1.03 m. (Assume that the positive direction is upward.) (a) Calculate its velocity just before it strikes the floor. (b) Calculate its velocity just after it leaves the floor on its way back up. -Answer is 4.49 m/s (c) Calculate its acceleration during contact with the floor if that contact lasts 3.50 ms. (d) How much did the...
A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.13 m. (Assume that the positive direction is upward.) (a) Calculate its velocity just before it strikes the floor, in m/s. (b) Calculate its velocity just after it leaves the floor on its way back up, in m/s. (c) Calculate its acceleration (in m/s^2) during contact with the floor if that contact lasts 3.50 ms. (d) How much...
A steel ball is dropped onto a hard floor from a height of 1.575 m and rebounds to a height of 1.3 m. Use a coordinate system in which the vertical component of velocity is positive in the upwards direction. Part (a) Calculate its velocity, in meters per second, just before it strikes the floor.
A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (Assume that the positive direction is upward. Indicate the direction of velocities and accelerations with the sign of your answer.) (a) Calculate its velocity (in m/s) just before it strikes the floor. (b) Calculate its velocity (in m/s) just after it leaves the floor on its way back up. (c) Calculate its acceleration (in m/s2) during...
A steel ball is dropped onto a hard floor from a height of 1.95 m and rebounds to a height of 1.89m. (Assume that the positive direction is upward.) (a) Calculate its velocity (in m/s) just before it strikes the floor (b) Calculate its velocity (in m/s) just after it leaves the floor on its way back up(c) Calculate its acceleration (in m/s) during contact with the floor if that contact lasts 0.0800 ms (d) How much (in ) did the ball compress...