ZuoTi.Pro
Question

Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the...

Consider the following. (Round your answers to two decimal places.)

(a) Determine the value of the confidence coefficient z(α/2) for 1 − α = 0.89.


(b) Determine the value of the confidence coefficient z(α/2) for 1 − α = 0.94.

Two hundred fish caught in Cayuga Lake had a mean length of 14.4 inches. The population standard deviation is 3.5 inches. (Give your answer correct to two decimal places.)

(c) Find the 90% confidence interval for the population mean length.

Lower Limit
Upper Limit


(d) Find the 98% confidence interval for the population mean length.

Lower Limit
Upper Limit
math   Statistics-And-Probability   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

(a) Step 1: The value of the confidence coefficient is 1-a-0.89 a 1-0.89 0.11 α=0.11 a 0.11 → 0.055 0.055 Step2: The area under the normal curve is less than z is 0.055 The value of the confi dence coefficient is obtained by using the excel function normsin v(0.055) -1.59819 Step3: Therefore, the value of the confidence coefficient is Z 0.11 Z01.60 0055 b) Step1: The value of the confi dence coefficient is 1-a 0.94 a1-0.94 0.06 a0.06 a0.06 0.03 0.03 Step2: The area under the normal curve is less than z is 0.03 The value of the confi dence coefficient is obtained by using the excel function normsin v(0.03) 1.88079 Step3: Therefore, the value of the confidence coefficient is Z 006 1.88 003

c) The sample size is n 200 The sample mean is X= 14.4inches The sample standard deviation is s-3.5inches The standard error for the mean is 3.5 200 3.5 14.14214 0.247487 SE7-0.247487 The critical values of the normal distributi on is Z/2 -Z0.10/2 →2005 = 1.645 200s1.645 The formula for calculating the margin of error is 1.645(0247487) 0.407117 Е 04071 17 The formula for calculating the 90% confidence interval for the population mean is 14.4-0.4071 17 μ 14.4 0.407117 13.99288 S14.80712 X-E μ X+5-139929 μ 14.8071 Interpretat on We can be 90% confident that the population mean length is between The lower liit X-E 13.99 The upper limit XE14.81

d) The sample size is n 200 The sample mean is X-14.4inches The sample standard deviation is s-3.5inches The standard error for the mean is SE,- 3.5 200 3.5 14.14214 0.247487 SEx -0.247487 The critical values of the normal distributi on is Z2Zoo2/2 2001 2.32635 2001 2.3.3 The formula for calculating the margin of error is 2.33(0.247487) 0.576646 8-0 576646| The formula for calculating the 98% confidence interval for the population mean is 14.4-0.576646 H14.40.576646 13.82335 SHS14.97665 X-E μ X+E-13.8234 μ 14.9767 Interpretati on: We can be 98% confident that the population mean length is between The lower limit X-E13.82 The upper lit X 1 14.98

0 0
Add a comment
Know the answer?
Add Answer to:
Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • Two hundred fish caught in Cayuga Lake had a mean length of 14.4 inches. The population...

    Two hundred fish caught in Cayuga Lake had a mean length of 14.4 inches. The population standard deviation is 2.7 inches. (Give your answer correct to two decimal places.) (a) Find the 90% confidence interval for the population mean length. Lower Limit _______ Upper Limit _______ (b) Find the 98% confidence interval for the population mean length. Lower Limit ________ Upper Limit ________

  • Two hundred fish caught in Cayuga Lake had a mean length of 13.7 inches. The population...

    Two hundred fish caught in Cayuga Lake had a mean length of 13.7 inches. The population standard deviation is 3.4 inches. (Give your answer correct to two decimal places.) (a) Find the 90% confidence interval for the population mean length. Lower Limit ______ Upper Limit ______ (b) Find the 98% confidence interval for the population mean length. Lower Limit ______ Upper Limit ______ You may need to use the appropriate table in Appendix B to answer this question.

  • Two hundred fish caught in Cayuga Lake had a mean length of 14.9 inches. The population...

    Two hundred fish caught in Cayuga Lake had a mean length of 14.9 inches. The population standard deviation is 3.5 inches. (Give your answer correct to two decimal places.) (a) Find the 90% confidence interval for the population mean length. Lower Limit Upper Limit (b) Find the 98% confidence interval for the population mean length. Lower Limit Upper Limit You may need to use the appropriate table in Appendix B to answer this question

  • 6 O-9.09 points JKES11& E 037 МУ Notes * Two hundred fish caught in Cayuga Lake...

    6 O-9.09 points JKES11& E 037 МУ Notes * Two hundred fish caught in Cayuga Lake had a mean length of 13 inches. The population standard deviation is 2.5 inches. (Give your answer correct to two decimal places.) (a) Find the 90% confidence interval for the population mean length Lower Limit Upper Limit (b) Find the 98% confidence interval for the population mean length. Lower Limit Upper Limit You may need to use the appropriate table in Appendix B to...

  • Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the...

    Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the confidence coefficient z(α/2) for 1 − α = 0.81. (b) Determine the value of the confidence coefficient z(α/2) for 1 − α = 0.93. You may need to use the appropriate table in Appendix B to answer this question.

  • Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the...

    Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the confidence coefficient z(α/2) for 1 − α = 0.85. (b) Determine the value of the confidence coefficient z(α/2) for 1 − α = 0.93. You may need to use the appropriate table in Appendix B to answer this question.

  • Suppose in a popular fishing lake, 10 largemouth bass are caught, and each of their lengths...

    Suppose in a popular fishing lake, 10 largemouth bass are caught, and each of their lengths (in inches) are recorded below: Length Fish #1 #2 3 #4 #5 #6 7 #8 #9 #10 ches, 17.1 15.0 15.8 15.2 17.117.713.0 15.4 16.8 12.1 Furthermore, suppose it is known that the population standard deviation for length is o distributed = 1.04, and that the length of largemouth bass is normally a) What is a point estimate of the population mean length? Round...

  • +/-/9.09 points JKEStat11 8E022. Consider the following. (Round your answers to two decimal places.) (a) Determine...

    +/-/9.09 points JKEStat11 8E022. Consider the following. (Round your answers to two decimal places.) (a) Determine the value of the confidence coefficient z(a/2) for 1-α = 0.82. (b) Determine the value of the confidence coefficient z(a/2) for 1-α-0.99. You may need to use the appropriate table in Appendix B to answer this question. Need Help?Read It Talk to a Tutor

  • For this problem, carry at least four digits after the decimal in your calculations. Answers may...

    For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. Case studies showed that out of 10,800 convicts who escaped from certain prisons, only 8240 were recaptured. (a) Let p represent the proportion of all escaped convicts who will eventually be recaptured. Find a point estimate for p. (Round your answer to four decimal places.) (b) Find a 99% confidence interval for p. (Round your answers to three decimal...

  • Do not answer if you are not willing to complete all of the prompts Please Also...

    Do not answer if you are not willing to complete all of the prompts Please Also circle the final answer thank you Construct a 98% confidence interval to estimate the population mean when x=69 and s-14.2 for the sample sizes below. a) n 15 b) n 38 c)n-57 a) The 98% confidence interval for the population mean when n = 15 is from a lower limit of 5938 to an upper limit of 7862 Round to two decimal places as...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT