Question

*HonOuο Τ μα Χs Τ0.5 Σ ΣΥ.νε ΑΙ M -M ΑΕΙ 2Σ Α -Ι 3Σ(Υ-) Sooτ , νο n Μ -> δ Αυl Ε ssν ΑΕΙ Μη Ex(3,- =(3Y, - (31 3 (31) -D+(3(4- s) -1 43 + + Lt Alaobnic Popates .>(Υ.-.) -Σ Υ.Σ CYi 12 320nC Ε. Σ 4 8-8-8 8*8 3 St40 n 8+88 3(8) -34 Ex & 4=3 C-(Uppr-Laoer+C EL 11

Answer 1

EXampe 4 6 8 10 H t4t6+810 3 5 7 9Ay X: 5 1 3+579 y : (ax)4(4x 3) + ( 6x5)4 (gx 7)+ (tox9) e t1+ 30 +56+90 30 6Ab Mx Hy Q5 0CT =5 i-H)2-6) + (4-6) + (6-6 X8-6)+ (io-6) -4-2+o +2 t.4 Seon of deviation about mean a-6)((6b+ (8-6) (10-6)7 + (6-6) +0+4+16 16 4 5 40 11 8 Standard deiation, x

5 TU-5(8-5(5-5+7-5)4 C9-) bt4 t0+4+1 Standard devaton, oy ve 64 a.898 (y-M -5 +(35) - (5-6)+(T-5) +(9-5) 3. 1: C)+r Algebraic Poopefe ;nニ5 EKOTEY T. 21 (xY)x 6914+3)+ 1645) + (6+7)7 (10+9) = (xi) 121 o) 1+3+57+9) (2+4+ 6+8 +10 30t85 + My x: +2 x - y.)- ta-1) +(4-3)+ (6-5) +(8-7) + (1o-9) Suniady

2(x4:) =5 Br- &+4ナ6+8+10-1-3-5-ワー9 y0 =5G :-Ay 2:) C4 lhay) CEXR Cx 3cr (4x2)+(4メ4)+(4x6) +(4x8) +(4x10) 120 A 4 x 30 2 Cx-2X 121 2e-ne 4 5 x4 20 三(uppes -Louer +))e 4. 4-(5-3)t1)4 3メ4 18