An initial value problem and its exact solution y(x) are given. Apply Euler’s method twice to approximate to this solution on the inteival [0. ½], first with step size h = 0.25, then with step size h = 0.1. Compare the three-deeimal-place values of the two approximations at x = ½ with the value y(½) of the actual solution.
y′ = y − x − 1, y(0) = 1; y(x) = 2 + x − ex
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