In Exercise, use the Gauss-Jordan method to find the inverse of the given matrix (if it exists).
Reference Gauss-Jordan method
We can perform row operations on A and I simultaneously by constructing a “superaugmented matrix” [A|I ]. Theorem 3.14 shows that if A is row equivalent to I [which, by the Fundamental Theorem (d) (a), means that A is invertible], then elementary row operations will yield
(A | I ) → (I | A–1 )
If A cannot be reduced to I, then the Fundamental Theorem guarantees us that A is
not invertible.
The procedure just described is simply Gauss-Jordan elimination performed on an n × 2n, instead of an n × (n + 1), augmented matrix. Another way to view this procedure is to look at the problem of finding A–1 as solving the matrix equation AX=In for an n × n matrix X. (This is sufficient, by the Fundamental Theorem, since a right inverse of A must be a two-sided inverse.) If we denote the columns of X by x1, . . . , xn, then this matrix equation is equivalent to solving for the columns of X, one at a time. Since the columns of In are the standard unit vectors e1, . . . , en, we thus have n systems of linear equations, all with coefficient matrix A:
A x 1 = e1, . . . , Axn = en
Since the same sequence of row operations is needed to bring A to reduced row echelon form in each case, the augmented matrices for these systems, [A | e1], . . . , [A | en], can be combined as
[A | e1 e2 . . . en ] = (A | In )
We now apply row operations to try to reduce A to In, which, if successful, will simultaneously solve for the columns of A–1, transforming In into A–1.
We illustrate this use of Gauss-Jordan elimination with three examples.
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