Define the sequence c0, c1, ... by the equations
C0 = 0, cn = c[n/2] + 3 for-all n > 0.
What is wrong with the following “proof” that cn ≤ 2n for all n ≥ 3? (You should verify that it is false that cn ≤ 2n for all n ≥ 3.)
We use the Strong Form of Mathematical Induction.
Basis Step (n = 3)
We have
c3 = c1 + 3 = (c0 + 3) + 3 = 6 ≤ 2.3.
The Basis Step is verified.
Inductive Step
Assume that ck ≤ 2k for all k < n. Then
cn = c[n/2] +3 ≤ 2[n/2] + 3 < 2(n/2)+3 = n+3 < n+n = 2n,
(Since 3 < n, n + 3 < n + n.) The Inductive Step is complete.
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