Problem

Example (h) illustrates a technique for showing that any repeating decimal number is ratio...

Example (h) illustrates a technique for showing that any repeating decimal number is rational. A calculator display shows the result of a certain calculation as 40.72727272727. Can you be sure that the result of the calculation is a rational number? Explain.

Example

Determining Whether Numbers Are Rational or Irrational

a. Is 10/3 a rational number?


b. Is −  a rational number?


c. Is 0.281 a rational number?


d. Is 7 a rational number?


e. Is 0 a rational number?


f. Is 2/0 a rational number?


g. Is 2/0 an irrational number?


h. Is 0.12121212 …a rational number (where the digits 12 are assumed to repeat forever)?


i. If m and n are integers and neither m nor n is zero, is (m + n)/mn a rational number?

Solution

a. Yes, 10/3 is a quotient of the integers 10 and 3 and hence is rational.


b. Yes, −  = − which is a quotient of the integers −5 and 39 and hence is rational.


c. Yes, 0.281 = 281/1000. Note that the real numbers represented on a typical calculator display are all finite decimals. An explanation similar to the one in this example shows that any such number is rational. It follows that a calculator with such a display can represent only rational numbers.


d. Yes, 7 = 7/1.


e. Yes, 0 = 0/1.


f. No, 2/0 is not a number (division by 0 is not allowed).


g. No, because every irrational number is a number, and 2/0 is not a number. We discuss additional techniques for determining whether numbers are irrational in Sections.


h. Yes. Let x = 0.12121212 …Then 100x = 12.12121212 …Thus

100xx = 12.12121212 …− 0.12121212 …= 12.

But also 100xx = 99x by basic algebra

Hence 99x = 12,

and so 

Therefore, 0.12121212 …= 12/99, which is a ratio of two nonzero integers and thus is a rational number.

Note that you can use an argument similar to this one to show that any repeating decimal is a rational number. In Section 9.4 we show that any rational number can be written as a repeating or terminating decimal.

i. Yes, since m and n are integers, so are m + n and mn (because sums and products of integers are integers). Also mn ≠ 0 by the zero product property. One version of this property says the following:

Zero Product Property

If neither of two real numbers is zero, then their product is also not zero.

(See Theorem and exercise 1 at the end of this section.) It follows that (m + n)/mn is a quotient of two integers with a nonzero denominator and hence is a rational number.

Theorem

T11. Zero Product Property If ab = 0, then a = 0 or b = 0.

Exercise 1

Determine which statement are true and which are false. Prove those that are true and disprove those that are false.

Exercise

The difference of any two irrational numbers is irrational.

Step-by-Step Solution

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Solutions For Problems in Chapter 3.7