Determine VD and VGS for the fixed-bias configuration of Fig. 7.79.FIG. 7.79

Due to the negative value of the gate source voltage, the drain current \(\left(I_{D}\right)\) is zero.

\(I_{D}=0 \mathrm{~mA}\)

Calculate the voltage at the drain terminal.

\(V_{D}=V_{D D}-I_{D} R_{D} \ldots \ldots\) (1)

Substitute \(18 \mathrm{~V}\) for \(V_{D D}, 2 \mathrm{k} \Omega\) for \(R_{D}\) and \(0 \mathrm{~mA}\) for \(I_{D}\) in equation (1).

\(\begin{aligned} V_{D} &=18-(0)\left(2 \times 10^{3}\right) \\ &=18-0 \\ &=18 \mathrm{~V} \end{aligned}\)

Therefore, the drain voltage \(\left(V_{D}\right)\) is \(18 \mathrm{~V}\)