Solve Problem 15.2 for the loading shown in Fig. P15.2 and a settlement of . at support B.
Given data:
Young’s modulus
Moment of inertia
Given figure:
Fixed end moments:
Slope deflection sign convention
Counterclockwise fixed end moments are considered as positive, and
Clockwise fixed end moments are considered as negative.
Chord rotation
Using
Slope deflection equations:
On further calculating:
Equilibrium equation:
Sum of moments at a joint is zero. Thus, we obtain the equilibrium equation
Therefore
Member end moments:
Now substituting the value in equation (1) to (4), to get the member end moments; Thus
Member end shear:
The member end shears, obtained by considering the equilibrium of each member.
By considering the member AB
Sum of moments about A is zero
Algebraic sum of vertical forces is zero
By considering the member BC
Sum of moments about C is zero
Algebraic sum of vertical forces is zero
To determine the vertical reaction at the roller support B, we consider the equilibrium of the joint B in the vertical direction, to obtain
Shear and bending moment diagrams