In the circuit of Fig. 6.34, i1(t) = 0.6e –2t A If i(0) = 1.4 A, find: (a) i2(0); (b) i2(t) and i(t); (c) v1(t), v2(t), and v(t).
Answer: (a) 0.8 A, (b) (−0.4 + 1.2e– 2t) A, (−0.4 + 1.8e–2t) A, (c) –36e–2t V, –7.2e–2tV, −28.8e-2t V.
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