Prove in absolute geometry that the total angle sum of two adjacent triangles with their bases lying on a common line exceeds the angle sum of the large triangle by 180, That is, if B-D-C and k1 and k2 are the angle sums of ∆BAD and ∆ADC, then k1 + k2 = m∠BAC + m∠B + m∠C + 180.
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