Repeat Problem with C = 1000(n + 100)/(n + 20) and R = 22.5n.
Problem
The relationship between the number n of items produced and the cost C of producing them is called the cost equation. The relationship between the number n of items produced and the revenue R (income) realized from their production is the revenue equation. The point at which the cost equals the revenue is the break-even point. Suppose that the cost equation is C = 0.0004π2 − 0.8n + 1000 and the revenue function is R = 0.6n. Graph these two equations on the same coordinate axes and find the break-even point(s). For what values of n does the revenue exceed the cost?
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