Problem

In general, squaring both sides of an equation is not reversible (if x = 2, then x2 = 4; b...

In general, squaring both sides of an equation is not reversible (if x = 2, then x2 = 4; but if x2 = 4, then x = ±2). Yet, in the proof of Theorem 4.1, the argument was declared to be reversible even though both sides of an equation were squared. Why?

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