Fill in the blanks for the following proof that the difference of any rational number and any irrational number is irrational.
Proof: Suppose not. That is, suppose that there exist (a) x and (b) y such that x − y is rational. By definition of rational, there exist integers a, b, c, and d with b ≠ 0 and d ≠ 0 so that x = (c) and x −y = (d). By substitution,
Adding y and subtracting on both sides gives
by algebra.
Now both ad − bc and bd are integers because products and differences of (f) are (g). And bd ≠ 0 by the (h). Hence y is a ratio of integers with a nonzero denominator, and thus y is (i) by definition of rational. We therefore have both that y is irrational and that y is rational, which is a contradiction. [Thus the supposition is false and the statement to be proved is true.]
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