Problem

Solutions For An Introduction to Genetic Analysis Chapter 19 Problem 18P

Step-by-Step Solution

Solution 1

The narrow-sense heritability h2 = 0.79

So, h2 < 1.0.

If h2 = 1, (Va = Vx) then the expected value for the offspring will be almost mid-parent value and total variance will be additive, which are heritable.

In this case, the narrow-sense heritability is closer to the population mean as h2 is 0.79

The expected value of the mean bill depth can be calculated as follows:

Male deviation = bill depth of the selected male – the mean bill depth of population

= 10.8 – 9.6 = 1.2

Female deviation = bill depth of selected female – the mean bill depth of population

= 9.8-9.6 = 0.2

Mean deviation = 1.2 + 0.2 /2 = 0.7

The mean deviation of the bill depth = 0.7. (If h2 = 1.0)

As h2 = 0.79, this will become 0.79 × 0.7 = 0.55

Hence, the expected mean for the offspring this selected pair = the mean bill depth of the population + the deviation from the population mean = 9.6+0.55= 10.15.

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