A uniformly distributed load on beam ABC in Figure P6.9 causes it to sag. To counteract th...

A uniformly distributed load on beam ABC in Figure P6.9 causes it to sag. To counteract this sag, a cable and post are added beneath the beam. The cable is tensioned until the force in the post causes a moment equal in magnitude, but opposite in direction, to the moment in the beam. Determine the forces in the cable and the post, and determine the reactions at A and C.

Figure P6.9: