The decomposition of crystalline N2O5
is an example of a reaction that is thermodynamically favored even though it absorbs heat. At 25 °C we have the following values for the standard state enthalpy and free energy changes of the reaction:
(a) Calculate ΔS° at 25 °C.
(b) Why is the entropy change so favorable for this reaction?
(c) Calculate ΔU° for this reaction at 25 °C.
(d) Why is ΔH° greater than ΔU°?
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