An integer is said to be square-free if it is not divisible by the square of any integer greater than 1. Prove the following:
(a) An integer n > 1 is square-free if and only if n can be factored into a product of distinct primes.
(b) Every integer n > 1 is the product of a square-free integer and a perfect square. [Hint: If is the canonical factorization of n, then write ki=2qi + ri where ri, = 0 or 1 according as ki, is even or odd.]
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.