Problem

If, for some constant m,for all x1 ≠ x2 , show that f(x) = mx+b, where b is some constant....

If, for some constant m,

for all x1 ≠ x2 , show that f(x) = mx+b, where b is some constant. [Hint: Fix x1 and take x = x2 ; then, solve for f(x).]

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Solutions For Problems in Chapter 1.1

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