You are asked to prepare a 0.8500 M solution of aluminum nitrate. You find that you have only 50.00 g of the solid.
(a) What is the maximum volume of solution that you can prepare?
(b) How many milliliters of this prepared solution are required to furnish 0.5000 mol of aluminum nitrate to a reaction?
(c) If 2.500 L of the prepared solution are required, how much more aluminum nitrate would you need?
(d) Fifty milliliters of a 0.450 M solution of aluminum nitrate are needed. How would you prepare the required solution from the solution prepared in (a)?
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