Equation 18.25 showed the preparation of [F3AsAuXe][Sb2F|J from [F3AsAu]|SbF6]. Solid [F3AsAu][SbF6]contains a distorted [SbF6|ion; one Sb-F bond is 193 pm long,and five are in the range 185-189 pm.The Au centre interacts with the F atom of the long Sb-F bond(Au-F=212 pm,compared with 203 pm calculated for the hypothetical[AuF2] ion).Suggest why [F3AsAu][SbF6]was chosen as the precursor to[F3AsAuXe|+,rather than a route involving reduction of AuF3 in an hydrous HF/SbF5 in the presence of Xe.
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