Calculate E0 for the process Cu(NH3)42+ + e- ⇌ Cu(NH3)2+ + 2NH3
given that Cu++2NH3 ⇌ Cu(NH3)2+ β2 = 7.2 × 1010
Cu2++4NH3 ⇌ Cu(NH3)42+ β4 = 5.62 × 1011
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.