(Light extinction)As light passes through window glass some of it is absorbed. If a: is a coordinate normal to the glass (withx= 0 at the incident face) andI(x)is the light intensity atx,then the fractional loss in intensity,—dI/I (with the minus sign included becausedlwill be negative), will be proportional todx: —dl/I = k dx,where A: is a positive constant. Thus,I(x)satisfies the differential equationI′(x)= −kI(x).The problem: If 80% of the light penetrates a 1-inch thick slab of this glass, how thin must the glass be to let 95% penetrate? NOTE: Your answer should be numerical, not in terms of an unknownk.
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