A bioengineer studying an injury sustained in throwing the javelin estimates that the magn...

Calculate the magnitude of moment of force vector \(\mathrm{F}\).

$$ \left|\mathbf{M}_{o}\right|=|\mathbf{F}|(d) $$

Here, \(\mathbf{F}\) is the force and \(d\) is the perpendicular distance.

Substitute \(360 \mathrm{~N}\) for \(\mathbf{F}\) and \(0.55 \mathrm{~m}\) for \(d\).

$$ \begin{aligned} \left|\mathbf{M}_{o}\right| &=(360 \mathrm{~N})(0.55 \mathrm{~m}) \\ &=198 \mathrm{~N}-\mathrm{m} \end{aligned} $$

Since, the vector \(\mathbf{F}\) and point \(O\) are contained in the \(x\) - \(y\) plane.

Moment vector is perpendicular to \(x\) - \(y\) plane. Right hand rule indicates that the moment vector \(\mathbf{M}_{o}\) points in the positive \(z\) -direction.

Therefore, the moment of force \(\mathbf{F}\) about the shoulder joint \(O\) as a vector is \((198 \mathbf{k}) \mathrm{N} \cdot \mathrm{m}\)