Based on numerical examples involving rectangles, the following conjecture is made: If P is any point on the diagonal of parallelogram ABCD, the parallel lines through P to the sides form two parallelograms having equal areas. Try proving it (there is a simple proof that does not involve ratios or similar triangles, only areas of parts of the given parallelogram). Do you agree with the conjecture in the case of a square?
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.