Problem

Linear systems are particularly easy to solve when they are in triangular form (i.e., al...

Linear systems are particularly easy to solve when they are in triangular form (i.e., all entries above or below the diagonal are zero).

a. Solve the lower triangular system

by forward substitution, finding x1 first, then x2, then x3, and finally x4.

b. Solve the upper triangular system

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