Find the power supplied by the 40-V source in the circuit in Fig. 2PFE-6.a. 120 Wb. 232 Wc...

By using Kirchhoff's current law calculate the value of current \(I\) in Figure 1 .

$$ \begin{aligned} I &=I_{1}+I_{2}+I_{3}+I_{4}+I_{5} \\ &=2 \mathrm{~A}+1.6 \mathrm{~A}+0.4 \mathrm{~A}+3 \mathrm{~A}-1.2 \mathrm{~A} \\ &=5.8 \mathrm{~A} \end{aligned} $$

Now, calculate the power supplied by \(40 \mathrm{~V}\) source in the circuit by using the formula \(P=V I\).

Substitute \(P=P_{40 \mathrm{v}}, V=40 \mathrm{~V}, I=5.8 \mathrm{~A}\) from Figure 1 and solve for \(P_{40 \mathrm{v}}\).

$$ \begin{aligned} P_{40 \mathrm{~V}} &=(40 \mathrm{~V})(5.8 \mathrm{~A}) \\ &=232 \mathrm{~W} \end{aligned} $$

Therefore, the value of power supplied by \(40 \mathrm{~V}\) source in the circuit is \(232 \mathrm{~W}\).