What’s wrong with this argument? Suppose x and y represent two real numbers, where x > y.
2 > 1 | This is a true statement. |
2(y − x) > 1(y − x) | Multiply both sides by y − x. |
2y − 2x > y − x | Use the distributive property. |
y − 2x > −x | Subtract y from both sides. |
y > x | Add 2x to both sides. |
The final inequality, y > x, is impossible because we were initially given x > y
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