Prove that the Fourier transform of the unit-step signal, u(t), is
where K = π. At first glance, it might seem that the impulse term Kδ(ω) should be zero, but show that K ≠ 0 because the following signal s(t) is an odd symmetric signal.
Note: Even though S(t) and u(t) differ at one isolated point, t = 0, they still have the same Fourier transform
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.