Find the average power absorbed by the network in Fig. P15.42 if
v(t) = 12 + 6 cos (377t − 10°) + 4 cos (754t − 60°)V
i(t) = 0.2 + 0.4 cos (377t − 150°)−0.2 cos (754t − 80°) + 0.1 cos (1131t − 60°) A
Figure P15.42
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