Consider the system of Figure P4.25 with h(t) = ae–atu(t), a > 0. This is a low-pass system.
(a) The input is x(t) = sin2(2t). Find y(t). Notice that the higher frequency components are attenuated more than the lower frequency components.
(b) Repeat Part (a) with a = 2 and x(t) = 10 + 5 cos (2t) + 5 cos (8t). Notice how much more the highest frequency component is attenuated relative to the lower frequency components.
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