A domestic wastewater with 220 mg/l of suspended solids, 180 mg/l of BOD, and 6.4 mg/l of phosphorus is treated by lime precipitation in primary settling followed by conventional activated-sludge processing. A dosage of 170 mg/l of CaO removes 80% of the influent phosphorus. Of the remaining 1.3 mg/l of phosphorus, 0.8 mg/l is removed by biological uptake during aeration and 0.5 mg/l appears in the plant effluent\Lime precipitation in the primary also removes 80% of the suspended solids and 60% of the BOD. The plant effluent suspended-solids concentration averages 20 mg/l. Calculate the estimated production of sludge solids per cubic meter of wastewater treated based on the following data: The chemical precipitate produced is 2.0 mg of calcium hydroxyapatite and calcium carbonate per 1.0 mg of CaO applied. The aeration process operates at an F/M of 0.2 g BOD/day/g MLSS. How does this sludge production compare to the sludge solids produced by the biological-chemical treatment in Problem 14.21?
Problem:
A conventional activated-sludge plant treats a domestic wastewater with 220 mg/l of suspended solids, 180 mg/l of BOD, and 6.4 mg/l of total phosphorus. After primary settling, the characteristics are 110 mg/l of suspended solids, 120 mg/l of BOD, and 5.4 mg/l of total phosphorus. Based on a pilot-plant study, a dosage of 116 mg/l of alum is required to reduce the effluent total phosphorus to 0.5 mg/l with the aeration tank operating at an F/M of 0.20 g BOD/day/g MLSS.The effluent suspended-solids concentration averages 10 mg/l. Calculate the estimated production of sludge solids per cubic meter of wastewater treated. If the primary sludge has a solids content of 5.0% and the waste sludge from the chemical-biological aeration system has a concentration of 1.5%, calculate the liters of combined sludge produced per cubic meter of wastewater treated.
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