Height of a projectile. The height, h, of a projectile thrown straight up from the top of a 480-foot hill t seconds after being thrown upward with initial velocity v0ft/sec is given by h = –16t2+ v 0t + 480. In Exercise, for a given value of v0, find the time(s) when the projectile will (a) be at a height of 592 ft above the ground and (b) crash on the ground. Round your answers to two decimal places.
v0 = 64
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