Problem

In Exercises, verify Theorem for the given sets.TheoremLet a, b, and c be integers.(a) If...

In Exercises, verify Theorem for the given sets.

Theorem

Let a, b, and c be integers.

(a) If a | b and a | c, then a | (b + c).


(b) If a | b and a | c, where b >c, then a | (bc).


(c) If a | b or a | c, then a | bc.


(d) If a | b and b | c, then a | c.

Proof

(a)If a | b and a | c, then b = k1a and c = k2a for integers k1 and k2. So b + c = (k1 + k2)a and a | (b + c).


(b) This can be proved in exactly the same way as (a).


(c) As in (a), we have b = k1a or c = k2a. Then either bc = k1ac or bc = k2ab, so in either case bc is a multiple of a and a | bc.


(d) If a | b and b | c, we have b = k1a and c = k2b, so c = k2b = k2(k1a) = (k2k1)a and hence a | c.

Exercise

(a) A = {a, b, c, d, e, f}, B = {a, c, f, g, h, i, r}


(b) A = {a, b, c, d, e}, B = {f, g, r, s, t, u}

Step-by-Step Solution

Request Professional Solution

Request Solution!

We need at least 10 more requests to produce the solution.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the solution will be notified once they are available.
Add your Solution
Textbook Solutions and Answers Search