Problem

In order for a proof by mathematical induction to be valid, the basis statement must be tr...

In order for a proof by mathematical induction to be valid, the basis statement must be true for n = a and the argument of the inductive step must be correct for every integer k ≥ a. In Find the mistakes in the “proofs” by mathematical induction.

Exercise

 “Theorem:” For all integers n > 1,3n 2 is even.

Proof (by mathematical induction): Suppose the theorem is true for an integer k, where k ≥ 1. That is, suppose that 3k – 2 is even. We must show that 3k+1 –2 is even. But

Now 3k – 2 is even by inductive hypothesis and 3k • 2 is even by inspection. Hence the sum of the two quantities is even (by Theorem). It follows that 3k+1 – 2 is even, which is what we needed to show.”

Theorem

The sum of any two even integers is even.

Proof:

Suppose m and n are [particular but arbitrarily chosen] even integers. [We must show that m + n is even.] By definition of even, m = 2r and n = 2s for some integers r and s. Then

Let t = r + s. Note that t is an integer because it is a sum of integers. Hence

m + n = 2t where t is an integer.

It follows by definition of even that m + n is even. [This is what we needed to show.]

Step-by-Step Solution

Request Professional Solution

Request Solution!

We need at least 10 more requests to produce the solution.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the solution will be notified once they are available.
Add your Solution
Textbook Solutions and Answers Search
Solutions For Problems in Chapter 4.3