Exercises 49–53 involve Definition 2.2 of the limit.
Consider the function f (x, y) = 2x − 10y + 3.
(a) Show that if ||(x, y) − (5, 1)|| < δ, then |x − 5| < δ and |y − 1| < δ.
(b) Use part (a) to show that if ||(x, y) − (5, 1)|| < δ, then | f (x, y) − 3| < 12δ.
(c) Show that lim(x,y)→(5,1) f (x, y) = 3.
We need at least 10 more requests to produce the solution.
0 / 10 have requested this problem solution
The more requests, the faster the answer.