Converse of Triangle Inequality Theorem Use the Two Circle Theorem (Problem 21) to prove in absolute geometry that if three numbers a, b, and c satisfy the (strict) Triangle Inequality (that is, a + b > c, a + c > b, and b + c > a), then there exists a triangle ∆ABC having a, b, and c as the lengths of its sides. Thus,
COROLLARY: Given a segment , there exists an equilateral triangle ∆ABC having as base.
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