Determine the static or dc resistance of the commercially available diode of Fig. at a reverse voltage of –10 V. How does it compare to the value determined at a reverse voltage of –30 V?
FIG. Silicon semiconductor diode characteristics.
Refer to the diode characteristics of Figure \(1.15\) in the text book.
Dashed line plot in the characteristics is for \(V_{D}<0 \mathrm{~V}\).
Blue colour line in the characteristics is for \(V_{D}>0 \mathrm{~V}\).
The diode reverse voltage is, \(V_{D} \cong-10 \mathrm{~V}\).
Consider dashed line in the characteristics since the diode reverse voltage is \(V_{D}<0 \mathrm{~V}\)
From Figure \(1.15\), the diode current at \(V_{D} \cong-10 \mathrm{~V}\) is,
$$ I_{D}=-10 \mathrm{pA} $$
Calculate the static or the dc resistance \(R_{D C}\).
$$ R_{D C}=\frac{V_{D}}{I_{D}} $$
Substitute \(-10 \mathrm{pA}\) for \(I_{D}\) and \(-10 \mathrm{~V}\) for \(V_{D}\).
$$ \begin{aligned} R_{D C} &=\frac{-10 \mathrm{~V}}{-10 \mathrm{pA}} \\ &=10^{12} \Omega \\ &=1000 \mathrm{G} \Omega \end{aligned} $$
Hence, the static or the dc resistance \(R_{D C}\) is \(1000 \mathrm{G} \Omega\).
The diode reverse voltage is, \(V_{D} \cong-30 \mathrm{~V}\).
Consider dashed line in the characteristics since the diode reverse voltage is \(V_{D}<0 \mathrm{~V}\)
From Figure \(1.15\), the diode current at \(V_{D} \cong-30 \mathrm{~V}\) is,
$$ I_{D}=-10 \mathrm{pA} $$
Calculate the static or the dc resistance \(R_{D C}\).
$$ R_{D C}=\frac{V_{D}}{I_{D}} $$
Substitute \(-10 \mathrm{pA}\) for \(I_{D}\) and \(-30 \mathrm{~V}\) for \(V_{D}\).
$$ \begin{aligned} R_{D C} &=\frac{-30 \mathrm{~V}}{-10 \mathrm{pA}} \\ &=3 \times 10^{12} \Omega \\ &=3000 \mathrm{G} \Omega \end{aligned} $$
Hence, the static or the dc resistance \(R_{D C}\) is \(3000 \mathrm{G} \Omega\).
It is clear that the static resistance \(R_{D C}\) for \(V_{D} \cong-30 \mathrm{~V}\) is more than for \(V_{D} \cong-10 \mathrm{~V}\).