Double check the fact that the input x2[n] determined in Example 9-10 produces an output that is zero everywhere by substituting this signal into the difference equation y[n] = x[n] − 2x[n − 1] + 2x[n − 2] − x[n − 3] to show that the complex phasors cancel out for all values of n.
Also show that the filter nulls out signals such as 2 cos(πn/3), which is the sum of x2[n] and x3[n].
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