The no-bias transition capacitance of a silicon diode is 8 pF with VK = 0.7 V and n = 1/2. What is the transition capacitance if the applied reverse bias potential is 5 V?
The following is the expression for the transition capacitance :
Here,
Reverse biased voltage is 5 V,
Voltage is 0.7 V,
Capacitance is 8 pF,
Factor is .
Substitute the corresponding values to obtain transition capacitance :
Hence, the transition capacitance is .