Problem

The no-bias transition capacitance of a silicon diode is 8 pF with VK = 0.7 V and n = 1/2....

The no-bias transition capacitance of a silicon diode is 8 pF with VK = 0.7 V and n = 1/2. What is the transition capacitance if the applied reverse bias potential is 5 V?

Step-by-Step Solution

Solution 1

The following is the expression for the transition capacitance :

Here,

Reverse biased voltage is 5 V,

Voltage is 0.7 V,

Capacitance is 8 pF,

Factor is .

Substitute the corresponding values to obtain transition capacitance :

Hence, the transition capacitance is .

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