Problem

A solution consisting of 25.00 g NH4Cl in 178 mL of water is titrated with 0.114 M KOH....

A solution consisting of 25.00 g NH₄Cl in 178 mL of water is titrated with 0.114 M KOH.

(a) How many milliliters of KOH are required to reach the equivalence point?

(b) Calculate at the equivalence point. (Assume that volumes are additive.)

(c) What is the pH at the equivalence point?

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Solutions For Problems in Chapter 14

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